If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2*x)/5-x = x/10-(21/2)
3 = k/1.5
Y = (4/9)*x^2
3*x-5-1;2*x+2*y-6
x+y-7;y-x-3
| x-7=9+x | | (2x/5)-x=(x/10)-21/2 | | 3m-(-17m)-1-16-15m= | | 0.25x+8.25=0.75x+9.75 | | x^2+3x+2+ax+2a= | | 3=k/1.5 | | 11x+8.50=10.50x+10 | | y=-2x^2-16x-32 | | 6(3z-1)-5(z+1)=6(z+1) | | 2-(-2u+9)=9u+4 | | p^2+1-10p=0 | | 6a-2b+7ab-6b-3ab= | | 6x-200=17700 | | 7x-200=17700 | | Y=4/9x^2 | | 7x+200=17700 | | 6x+200=17700 | | 7x+3y=78 | | 2c-6=2 | | 6y-8=9y+13 | | (y+2)dx+(x-2)dy=0 | | x^2+0.02044536x-(0.0002657894985)=0 | | -7(t-9)-(t+8)=11 | | 2(3.2727)-9y=-8 | | 0=-4.9t^2-3t+950 | | 3a+4b=-8b+x | | x^2+3.98x-.05057=0 | | 3a+4b=x-8b | | -2h-6h+9h=3b-2b | | 4m^3(-5m^2+3m-2)=0 | | -2h-6h+8h=3b-2b | | -3h-6h+8h=3b-2b |